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Author:  JamesD [ Tue Feb 20, 2007 8:01 am ]
Post subject:  Can someone explain displaying floating point values?

Hi

I'm having a bit of trouble displaying floating point values that make sense.

Can anyone explain why the code below is displaying the following:

x= 536870912
PI= 1610612736

Does the display show decimals? Why doesn't the display show

x= 7.89
PI= 3.142 etc

 Code:task main(){   float x;    eraseDisplay();   x= 7.89;    nxtDisplayTextLine(1, "x = %d", x);    nxtDisplayTextLine(4, "PI = %d", PI);   wait1Msec(10000); //pause ten seconds}}

Thanks
James

Author:  JamesD [ Wed Feb 21, 2007 9:44 pm ]
Post subject:

To answer my own email in the interest of others who may follow.

To correctly display floating point variables you need to define how many decimal points you want displayed in the format shown below.

 Code:task main() { float x;    x= (60/180.0); eraseDisplay(); nxtDisplayTextLine(1, "x = %+5.3f", x); nxtDisplayTextLine(4, "PI = %+5.3f", PI); wait1Msec(10000); //pause ten seconds }

Another thing to note is that, in order for x to be a decimal/floating point the 180 needs to be written as 180.0 (otherwise x displays 0). Is this intentional? Is it a convention of C based languages? This took me quite a while to work out.

Thanks
James

 Author: Dick Swan [ Mon Feb 26, 2007 5:01 am ] Post subject: Regarding evaluating the equation "x = 60 / 180;" where 'x' is a 'float' variable. This is the behavior of the standard C language. Here's what is happening: Arithmetic expressions are evaluated using the type of the parameters('integer' or 'float'). so [int] / [int] is evaluated with integer arithmetic and results in an [int] result. If one of the operands is a [float] then floating point arithmetic will be used in the expression calculation.60 /180, using integer arithmetic results in 0. The result of the expression is converted to a floating point value (0.0) before it is stored in variable 'x'. So when you changed '180' to '180.0', the compiler then did the calculations using floating point arithmetic and you get the desired results of 0.3333. You'd get the same original results if the code was. int i = 60; int j = 180; float x; x = i/j; There is a way to force the compiler to use floating point arithmetic in the above. You use a "cast" statement which converts one 'type' to another. The last line above would be replaced with x = i / (float) j; The "(float)" is a 'cast' modifier which says convert the expression to the right to a 'float' value. There's a lot more powerful things that you can do with 'cast' but can't be covered here.

 Author: JamesD [ Tue Feb 27, 2007 6:52 am ] Post subject: Dear Dick, Thank you for elaborating on this topic. Very helpful. James

Author:  Miguel Angel [ Fri Mar 16, 2007 11:14 pm ]
Post subject:  Re: Can someone explain displaying floating point values?

 Code:task main(){   float x;    eraseDisplay();   x= 7.89;    nxtDisplayTextLine(1, "x = %d", x);    nxtDisplayTextLine(4, "PI = %d", PI);   wait1Msec(10000); //pause ten seconds}}

Just change %d for %f in your code, I think it will work.

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